\(\int \frac {x^{9/2}}{(a+c x^4)^3} \, dx\) [758]

Optimal result

Integrand size = 15, antiderivative size = 332 \[ \int \frac {x^{9/2}}{\left (a+c x^4\right )^3} \, dx=-\frac {x^{3/2}}{8 c \left (a+c x^4\right )^2}+\frac {3 x^{3/2}}{64 a c \left (a+c x^4\right )}-\frac {15 \arctan \left (1-\frac {\sqrt {2} \sqrt [8]{c} \sqrt {x}}{\sqrt [8]{-a}}\right )}{256 \sqrt {2} (-a)^{13/8} c^{11/8}}+\frac {15 \arctan \left (1+\frac {\sqrt {2} \sqrt [8]{c} \sqrt {x}}{\sqrt [8]{-a}}\right )}{256 \sqrt {2} (-a)^{13/8} c^{11/8}}-\frac {15 \arctan \left (\frac {\sqrt [8]{c} \sqrt {x}}{\sqrt [8]{-a}}\right )}{256 (-a)^{13/8} c^{11/8}}+\frac {15 \text {arctanh}\left (\frac {\sqrt [8]{c} \sqrt {x}}{\sqrt [8]{-a}}\right )}{256 (-a)^{13/8} c^{11/8}}+\frac {15 \log \left (\sqrt [4]{-a}-\sqrt {2} \sqrt [8]{-a} \sqrt [8]{c} \sqrt {x}+\sqrt [4]{c} x\right )}{512 \sqrt {2} (-a)^{13/8} c^{11/8}}-\frac {15 \log \left (\sqrt [4]{-a}+\sqrt {2} \sqrt [8]{-a} \sqrt [8]{c} \sqrt {x}+\sqrt [4]{c} x\right )}{512 \sqrt {2} (-a)^{13/8} c^{11/8}} \]

[Out]

-1/8*x^(3/2)/c/(c*x^4+a)^2+3/64*x^(3/2)/a/c/(c*x^4+a)-15/256*arctan(c^(1/8)*x^(1/2)/(-a)^(1/8))/(-a)^(13/8)/c^
(11/8)+15/256*arctanh(c^(1/8)*x^(1/2)/(-a)^(1/8))/(-a)^(13/8)/c^(11/8)+15/512*arctan(-1+c^(1/8)*2^(1/2)*x^(1/2
)/(-a)^(1/8))/(-a)^(13/8)/c^(11/8)*2^(1/2)+15/512*arctan(1+c^(1/8)*2^(1/2)*x^(1/2)/(-a)^(1/8))/(-a)^(13/8)/c^(
11/8)*2^(1/2)+15/1024*ln((-a)^(1/4)+c^(1/4)*x-(-a)^(1/8)*c^(1/8)*2^(1/2)*x^(1/2))/(-a)^(13/8)/c^(11/8)*2^(1/2)
-15/1024*ln((-a)^(1/4)+c^(1/4)*x+(-a)^(1/8)*c^(1/8)*2^(1/2)*x^(1/2))/(-a)^(13/8)/c^(11/8)*2^(1/2)

Rubi [A] (verified)

Time = 0.24 (sec) , antiderivative size = 332, normalized size of antiderivative = 1.00, number of steps used = 16, number of rules used = 13, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.867, Rules used = {294, 296, 335, 306, 303, 1176, 631, 210, 1179, 642, 304, 211, 214} \[ \int \frac {x^{9/2}}{\left (a+c x^4\right )^3} \, dx=-\frac {15 \arctan \left (1-\frac {\sqrt {2} \sqrt [8]{c} \sqrt {x}}{\sqrt [8]{-a}}\right )}{256 \sqrt {2} (-a)^{13/8} c^{11/8}}+\frac {15 \arctan \left (\frac {\sqrt {2} \sqrt [8]{c} \sqrt {x}}{\sqrt [8]{-a}}+1\right )}{256 \sqrt {2} (-a)^{13/8} c^{11/8}}-\frac {15 \arctan \left (\frac {\sqrt [8]{c} \sqrt {x}}{\sqrt [8]{-a}}\right )}{256 (-a)^{13/8} c^{11/8}}+\frac {15 \text {arctanh}\left (\frac {\sqrt [8]{c} \sqrt {x}}{\sqrt [8]{-a}}\right )}{256 (-a)^{13/8} c^{11/8}}+\frac {15 \log \left (-\sqrt {2} \sqrt [8]{-a} \sqrt [8]{c} \sqrt {x}+\sqrt [4]{-a}+\sqrt [4]{c} x\right )}{512 \sqrt {2} (-a)^{13/8} c^{11/8}}-\frac {15 \log \left (\sqrt {2} \sqrt [8]{-a} \sqrt [8]{c} \sqrt {x}+\sqrt [4]{-a}+\sqrt [4]{c} x\right )}{512 \sqrt {2} (-a)^{13/8} c^{11/8}}+\frac {3 x^{3/2}}{64 a c \left (a+c x^4\right )}-\frac {x^{3/2}}{8 c \left (a+c x^4\right )^2} \]

[In]

Int[x^(9/2)/(a + c*x^4)^3,x]

[Out]

-1/8*x^(3/2)/(c*(a + c*x^4)^2) + (3*x^(3/2))/(64*a*c*(a + c*x^4)) - (15*ArcTan[1 - (Sqrt[2]*c^(1/8)*Sqrt[x])/(
-a)^(1/8)])/(256*Sqrt[2]*(-a)^(13/8)*c^(11/8)) + (15*ArcTan[1 + (Sqrt[2]*c^(1/8)*Sqrt[x])/(-a)^(1/8)])/(256*Sq
rt[2]*(-a)^(13/8)*c^(11/8)) - (15*ArcTan[(c^(1/8)*Sqrt[x])/(-a)^(1/8)])/(256*(-a)^(13/8)*c^(11/8)) + (15*ArcTa
nh[(c^(1/8)*Sqrt[x])/(-a)^(1/8)])/(256*(-a)^(13/8)*c^(11/8)) + (15*Log[(-a)^(1/4) - Sqrt[2]*(-a)^(1/8)*c^(1/8)
*Sqrt[x] + c^(1/4)*x])/(512*Sqrt[2]*(-a)^(13/8)*c^(11/8)) - (15*Log[(-a)^(1/4) + Sqrt[2]*(-a)^(1/8)*c^(1/8)*Sq
rt[x] + c^(1/4)*x])/(512*Sqrt[2]*(-a)^(13/8)*c^(11/8))

Rule 210

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(-(Rt[-a, 2]*Rt[-b, 2])^(-1))*ArcTan[Rt[-b, 2]*(x/Rt[-a, 2])
], x] /; FreeQ[{a, b}, x] && PosQ[a/b] && (LtQ[a, 0] || LtQ[b, 0])

Rule 211

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[a/b, 2]/a)*ArcTan[x/Rt[a/b, 2]], x] /; FreeQ[{a, b}, x]
&& PosQ[a/b]

Rule 214

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[-a/b, 2]/a)*ArcTanh[x/Rt[-a/b, 2]], x] /; FreeQ[{a, b},
x] && NegQ[a/b]

Rule 294

Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[c^(n - 1)*(c*x)^(m - n + 1)*((a + b*x^
n)^(p + 1)/(b*n*(p + 1))), x] - Dist[c^n*((m - n + 1)/(b*n*(p + 1))), Int[(c*x)^(m - n)*(a + b*x^n)^(p + 1), x
], x] /; FreeQ[{a, b, c}, x] && IGtQ[n, 0] && LtQ[p, -1] && GtQ[m + 1, n] &&  !ILtQ[(m + n*(p + 1) + 1)/n, 0]
&& IntBinomialQ[a, b, c, n, m, p, x]

Rule 296

Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[(-(c*x)^(m + 1))*((a + b*x^n)^(p + 1)/
(a*c*n*(p + 1))), x] + Dist[(m + n*(p + 1) + 1)/(a*n*(p + 1)), Int[(c*x)^m*(a + b*x^n)^(p + 1), x], x] /; Free
Q[{a, b, c, m}, x] && IGtQ[n, 0] && LtQ[p, -1] && IntBinomialQ[a, b, c, n, m, p, x]

Rule 303

Int[(x_)^2/((a_) + (b_.)*(x_)^4), x_Symbol] :> With[{r = Numerator[Rt[a/b, 2]], s = Denominator[Rt[a/b, 2]]},
Dist[1/(2*s), Int[(r + s*x^2)/(a + b*x^4), x], x] - Dist[1/(2*s), Int[(r - s*x^2)/(a + b*x^4), x], x]] /; Free
Q[{a, b}, x] && (GtQ[a/b, 0] || (PosQ[a/b] && AtomQ[SplitProduct[SumBaseQ, a]] && AtomQ[SplitProduct[SumBaseQ,
b]]))

Rule 304

Int[(x_)^2/((a_) + (b_.)*(x_)^4), x_Symbol] :> With[{r = Numerator[Rt[-a/b, 2]], s = Denominator[Rt[-a/b, 2]]}
, Dist[s/(2*b), Int[1/(r + s*x^2), x], x] - Dist[s/(2*b), Int[1/(r - s*x^2), x], x]] /; FreeQ[{a, b}, x] &&  !
GtQ[a/b, 0]

Rule 306

Int[(x_)^(m_)/((a_) + (b_.)*(x_)^(n_)), x_Symbol] :> With[{r = Numerator[Rt[-a/b, 2]], s = Denominator[Rt[-a/b
, 2]]}, Dist[r/(2*a), Int[x^m/(r + s*x^(n/2)), x], x] + Dist[r/(2*a), Int[x^m/(r - s*x^(n/2)), x], x]] /; Free
Q[{a, b}, x] && IGtQ[n/4, 0] && IGtQ[m, 0] && LtQ[m, n/2] &&  !GtQ[a/b, 0]

Rule 335

Int[((c_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> With[{k = Denominator[m]}, Dist[k/c, Subst[I
nt[x^(k*(m + 1) - 1)*(a + b*(x^(k*n)/c^n))^p, x], x, (c*x)^(1/k)], x]] /; FreeQ[{a, b, c, p}, x] && IGtQ[n, 0]
&& FractionQ[m] && IntBinomialQ[a, b, c, n, m, p, x]

Rule 631

Int[((a_) + (b_.)*(x_) + (c_.)*(x_)^2)^(-1), x_Symbol] :> With[{q = 1 - 4*Simplify[a*(c/b^2)]}, Dist[-2/b, Sub
st[Int[1/(q - x^2), x], x, 1 + 2*c*(x/b)], x] /; RationalQ[q] && (EqQ[q^2, 1] ||  !RationalQ[b^2 - 4*a*c])] /;
FreeQ[{a, b, c}, x] && NeQ[b^2 - 4*a*c, 0]

Rule 642

Int[((d_) + (e_.)*(x_))/((a_.) + (b_.)*(x_) + (c_.)*(x_)^2), x_Symbol] :> Simp[d*(Log[RemoveContent[a + b*x +
c*x^2, x]]/b), x] /; FreeQ[{a, b, c, d, e}, x] && EqQ[2*c*d - b*e, 0]

Rule 1176

Int[((d_) + (e_.)*(x_)^2)/((a_) + (c_.)*(x_)^4), x_Symbol] :> With[{q = Rt[2*(d/e), 2]}, Dist[e/(2*c), Int[1/S
imp[d/e + q*x + x^2, x], x], x] + Dist[e/(2*c), Int[1/Simp[d/e - q*x + x^2, x], x], x]] /; FreeQ[{a, c, d, e},
x] && EqQ[c*d^2 - a*e^2, 0] && PosQ[d*e]

Rule 1179

Int[((d_) + (e_.)*(x_)^2)/((a_) + (c_.)*(x_)^4), x_Symbol] :> With[{q = Rt[-2*(d/e), 2]}, Dist[e/(2*c*q), Int[
(q - 2*x)/Simp[d/e + q*x - x^2, x], x], x] + Dist[e/(2*c*q), Int[(q + 2*x)/Simp[d/e - q*x - x^2, x], x], x]] /
; FreeQ[{a, c, d, e}, x] && EqQ[c*d^2 - a*e^2, 0] && NegQ[d*e]

Rubi steps \begin{align*} \text {integral}& = -\frac {x^{3/2}}{8 c \left (a+c x^4\right )^2}+\frac {3 \int \frac {\sqrt {x}}{\left (a+c x^4\right )^2} \, dx}{16 c} \\ & = -\frac {x^{3/2}}{8 c \left (a+c x^4\right )^2}+\frac {3 x^{3/2}}{64 a c \left (a+c x^4\right )}+\frac {15 \int \frac {\sqrt {x}}{a+c x^4} \, dx}{128 a c} \\ & = -\frac {x^{3/2}}{8 c \left (a+c x^4\right )^2}+\frac {3 x^{3/2}}{64 a c \left (a+c x^4\right )}+\frac {15 \text {Subst}\left (\int \frac {x^2}{a+c x^8} \, dx,x,\sqrt {x}\right )}{64 a c} \\ & = -\frac {x^{3/2}}{8 c \left (a+c x^4\right )^2}+\frac {3 x^{3/2}}{64 a c \left (a+c x^4\right )}+\frac {15 \text {Subst}\left (\int \frac {x^2}{\sqrt {-a}-\sqrt {c} x^4} \, dx,x,\sqrt {x}\right )}{128 (-a)^{3/2} c}+\frac {15 \text {Subst}\left (\int \frac {x^2}{\sqrt {-a}+\sqrt {c} x^4} \, dx,x,\sqrt {x}\right )}{128 (-a)^{3/2} c} \\ & = -\frac {x^{3/2}}{8 c \left (a+c x^4\right )^2}+\frac {3 x^{3/2}}{64 a c \left (a+c x^4\right )}+\frac {15 \text {Subst}\left (\int \frac {1}{\sqrt [4]{-a}-\sqrt [4]{c} x^2} \, dx,x,\sqrt {x}\right )}{256 (-a)^{3/2} c^{5/4}}-\frac {15 \text {Subst}\left (\int \frac {1}{\sqrt [4]{-a}+\sqrt [4]{c} x^2} \, dx,x,\sqrt {x}\right )}{256 (-a)^{3/2} c^{5/4}}-\frac {15 \text {Subst}\left (\int \frac {\sqrt [4]{-a}-\sqrt [4]{c} x^2}{\sqrt {-a}+\sqrt {c} x^4} \, dx,x,\sqrt {x}\right )}{256 (-a)^{3/2} c^{5/4}}+\frac {15 \text {Subst}\left (\int \frac {\sqrt [4]{-a}+\sqrt [4]{c} x^2}{\sqrt {-a}+\sqrt {c} x^4} \, dx,x,\sqrt {x}\right )}{256 (-a)^{3/2} c^{5/4}} \\ & = -\frac {x^{3/2}}{8 c \left (a+c x^4\right )^2}+\frac {3 x^{3/2}}{64 a c \left (a+c x^4\right )}-\frac {15 \tan ^{-1}\left (\frac {\sqrt [8]{c} \sqrt {x}}{\sqrt [8]{-a}}\right )}{256 (-a)^{13/8} c^{11/8}}+\frac {15 \tanh ^{-1}\left (\frac {\sqrt [8]{c} \sqrt {x}}{\sqrt [8]{-a}}\right )}{256 (-a)^{13/8} c^{11/8}}+\frac {15 \text {Subst}\left (\int \frac {1}{\frac {\sqrt [4]{-a}}{\sqrt [4]{c}}-\frac {\sqrt {2} \sqrt [8]{-a} x}{\sqrt [8]{c}}+x^2} \, dx,x,\sqrt {x}\right )}{512 (-a)^{3/2} c^{3/2}}+\frac {15 \text {Subst}\left (\int \frac {1}{\frac {\sqrt [4]{-a}}{\sqrt [4]{c}}+\frac {\sqrt {2} \sqrt [8]{-a} x}{\sqrt [8]{c}}+x^2} \, dx,x,\sqrt {x}\right )}{512 (-a)^{3/2} c^{3/2}}+\frac {15 \text {Subst}\left (\int \frac {\frac {\sqrt {2} \sqrt [8]{-a}}{\sqrt [8]{c}}+2 x}{-\frac {\sqrt [4]{-a}}{\sqrt [4]{c}}-\frac {\sqrt {2} \sqrt [8]{-a} x}{\sqrt [8]{c}}-x^2} \, dx,x,\sqrt {x}\right )}{512 \sqrt {2} (-a)^{13/8} c^{11/8}}+\frac {15 \text {Subst}\left (\int \frac {\frac {\sqrt {2} \sqrt [8]{-a}}{\sqrt [8]{c}}-2 x}{-\frac {\sqrt [4]{-a}}{\sqrt [4]{c}}+\frac {\sqrt {2} \sqrt [8]{-a} x}{\sqrt [8]{c}}-x^2} \, dx,x,\sqrt {x}\right )}{512 \sqrt {2} (-a)^{13/8} c^{11/8}} \\ & = -\frac {x^{3/2}}{8 c \left (a+c x^4\right )^2}+\frac {3 x^{3/2}}{64 a c \left (a+c x^4\right )}-\frac {15 \tan ^{-1}\left (\frac {\sqrt [8]{c} \sqrt {x}}{\sqrt [8]{-a}}\right )}{256 (-a)^{13/8} c^{11/8}}+\frac {15 \tanh ^{-1}\left (\frac {\sqrt [8]{c} \sqrt {x}}{\sqrt [8]{-a}}\right )}{256 (-a)^{13/8} c^{11/8}}+\frac {15 \log \left (\sqrt [4]{-a}-\sqrt {2} \sqrt [8]{-a} \sqrt [8]{c} \sqrt {x}+\sqrt [4]{c} x\right )}{512 \sqrt {2} (-a)^{13/8} c^{11/8}}-\frac {15 \log \left (\sqrt [4]{-a}+\sqrt {2} \sqrt [8]{-a} \sqrt [8]{c} \sqrt {x}+\sqrt [4]{c} x\right )}{512 \sqrt {2} (-a)^{13/8} c^{11/8}}+\frac {15 \text {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1-\frac {\sqrt {2} \sqrt [8]{c} \sqrt {x}}{\sqrt [8]{-a}}\right )}{256 \sqrt {2} (-a)^{13/8} c^{11/8}}-\frac {15 \text {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1+\frac {\sqrt {2} \sqrt [8]{c} \sqrt {x}}{\sqrt [8]{-a}}\right )}{256 \sqrt {2} (-a)^{13/8} c^{11/8}} \\ & = -\frac {x^{3/2}}{8 c \left (a+c x^4\right )^2}+\frac {3 x^{3/2}}{64 a c \left (a+c x^4\right )}-\frac {15 \tan ^{-1}\left (1-\frac {\sqrt {2} \sqrt [8]{c} \sqrt {x}}{\sqrt [8]{-a}}\right )}{256 \sqrt {2} (-a)^{13/8} c^{11/8}}+\frac {15 \tan ^{-1}\left (1+\frac {\sqrt {2} \sqrt [8]{c} \sqrt {x}}{\sqrt [8]{-a}}\right )}{256 \sqrt {2} (-a)^{13/8} c^{11/8}}-\frac {15 \tan ^{-1}\left (\frac {\sqrt [8]{c} \sqrt {x}}{\sqrt [8]{-a}}\right )}{256 (-a)^{13/8} c^{11/8}}+\frac {15 \tanh ^{-1}\left (\frac {\sqrt [8]{c} \sqrt {x}}{\sqrt [8]{-a}}\right )}{256 (-a)^{13/8} c^{11/8}}+\frac {15 \log \left (\sqrt [4]{-a}-\sqrt {2} \sqrt [8]{-a} \sqrt [8]{c} \sqrt {x}+\sqrt [4]{c} x\right )}{512 \sqrt {2} (-a)^{13/8} c^{11/8}}-\frac {15 \log \left (\sqrt [4]{-a}+\sqrt {2} \sqrt [8]{-a} \sqrt [8]{c} \sqrt {x}+\sqrt [4]{c} x\right )}{512 \sqrt {2} (-a)^{13/8} c^{11/8}} \\ \end{align*}

Mathematica [A] (verified)

Time = 1.38 (sec) , antiderivative size = 277, normalized size of antiderivative = 0.83 \[ \int \frac {x^{9/2}}{\left (a+c x^4\right )^3} \, dx=\frac {\frac {8 a^{5/8} c^{3/8} x^{3/2} \left (-5 a+3 c x^4\right )}{\left (a+c x^4\right )^2}+15 \sqrt {2-\sqrt {2}} \arctan \left (\frac {\sqrt {1-\frac {1}{\sqrt {2}}} \left (\sqrt [4]{a}-\sqrt [4]{c} x\right )}{\sqrt [8]{a} \sqrt [8]{c} \sqrt {x}}\right )-15 \sqrt {2+\sqrt {2}} \arctan \left (\frac {\sqrt {1+\frac {1}{\sqrt {2}}} \left (\sqrt [4]{a}-\sqrt [4]{c} x\right )}{\sqrt [8]{a} \sqrt [8]{c} \sqrt {x}}\right )+15 \sqrt {2-\sqrt {2}} \text {arctanh}\left (\frac {\sqrt {2+\sqrt {2}} \sqrt [8]{a} \sqrt [8]{c} \sqrt {x}}{\sqrt [4]{a}+\sqrt [4]{c} x}\right )-15 \sqrt {2+\sqrt {2}} \text {arctanh}\left (\frac {\sqrt [8]{a} \sqrt [8]{c} \sqrt {-\left (\left (-2+\sqrt {2}\right ) x\right )}}{\sqrt [4]{a}+\sqrt [4]{c} x}\right )}{512 a^{13/8} c^{11/8}} \]

[In]

Integrate[x^(9/2)/(a + c*x^4)^3,x]

[Out]

((8*a^(5/8)*c^(3/8)*x^(3/2)*(-5*a + 3*c*x^4))/(a + c*x^4)^2 + 15*Sqrt[2 - Sqrt[2]]*ArcTan[(Sqrt[1 - 1/Sqrt[2]]
*(a^(1/4) - c^(1/4)*x))/(a^(1/8)*c^(1/8)*Sqrt[x])] - 15*Sqrt[2 + Sqrt[2]]*ArcTan[(Sqrt[1 + 1/Sqrt[2]]*(a^(1/4)
- c^(1/4)*x))/(a^(1/8)*c^(1/8)*Sqrt[x])] + 15*Sqrt[2 - Sqrt[2]]*ArcTanh[(Sqrt[2 + Sqrt[2]]*a^(1/8)*c^(1/8)*Sq
rt[x])/(a^(1/4) + c^(1/4)*x)] - 15*Sqrt[2 + Sqrt[2]]*ArcTanh[(a^(1/8)*c^(1/8)*Sqrt[-((-2 + Sqrt[2])*x)])/(a^(1
/4) + c^(1/4)*x)])/(512*a^(13/8)*c^(11/8))

Maple [C] (verified)

Result contains higher order function than in optimal. Order 9 vs. order 3.

Time = 4.41 (sec) , antiderivative size = 61, normalized size of antiderivative = 0.18

method	result	size
derivativedivides	\(\frac {-\frac {5 x^{\frac {3}{2}}}{64 c}+\frac {3 x^{\frac {11}{2}}}{64 a}}{\left (x^{4} c +a \right )^{2}}+\frac {15 \left (\munderset {\textit {\_R} =\operatorname {RootOf}\left (c \,\textit {\_Z}^{8}+a \right )}{\sum }\frac {\ln \left (\sqrt {x}-\textit {\_R} \right )}{\textit {\_R}^{5}}\right )}{512 a \,c^{2}}\)	\(61\)
default	\(\frac {-\frac {5 x^{\frac {3}{2}}}{64 c}+\frac {3 x^{\frac {11}{2}}}{64 a}}{\left (x^{4} c +a \right )^{2}}+\frac {15 \left (\munderset {\textit {\_R} =\operatorname {RootOf}\left (c \,\textit {\_Z}^{8}+a \right )}{\sum }\frac {\ln \left (\sqrt {x}-\textit {\_R} \right )}{\textit {\_R}^{5}}\right )}{512 a \,c^{2}}\)	\(61\)

[In]

int(x^(9/2)/(c*x^4+a)^3,x,method=_RETURNVERBOSE)

[Out]

2*(-5/128*x^(3/2)/c+3/128/a*x^(11/2))/(c*x^4+a)^2+15/512/a/c^2*sum(1/_R^5*ln(x^(1/2)-_R),_R=RootOf(_Z^8*c+a))

Fricas [C] (verification not implemented)

Result contains complex when optimal does not.

Time = 0.29 (sec) , antiderivative size = 561, normalized size of antiderivative = 1.69 \[ \int \frac {x^{9/2}}{\left (a+c x^4\right )^3} \, dx=-\frac {15 \, \sqrt {2} {\left (\left (i - 1\right ) \, a c^{3} x^{8} + \left (2 i - 2\right ) \, a^{2} c^{2} x^{4} + \left (i - 1\right ) \, a^{3} c\right )} \left (-\frac {1}{a^{13} c^{11}}\right )^{\frac {1}{8}} \log \left (\left (\frac {1}{2} i + \frac {1}{2}\right ) \, \sqrt {2} a^{5} c^{4} \left (-\frac {1}{a^{13} c^{11}}\right )^{\frac {3}{8}} + \sqrt {x}\right ) + 15 \, \sqrt {2} {\left (-\left (i + 1\right ) \, a c^{3} x^{8} - \left (2 i + 2\right ) \, a^{2} c^{2} x^{4} - \left (i + 1\right ) \, a^{3} c\right )} \left (-\frac {1}{a^{13} c^{11}}\right )^{\frac {1}{8}} \log \left (-\left (\frac {1}{2} i - \frac {1}{2}\right ) \, \sqrt {2} a^{5} c^{4} \left (-\frac {1}{a^{13} c^{11}}\right )^{\frac {3}{8}} + \sqrt {x}\right ) + 15 \, \sqrt {2} {\left (\left (i + 1\right ) \, a c^{3} x^{8} + \left (2 i + 2\right ) \, a^{2} c^{2} x^{4} + \left (i + 1\right ) \, a^{3} c\right )} \left (-\frac {1}{a^{13} c^{11}}\right )^{\frac {1}{8}} \log \left (\left (\frac {1}{2} i - \frac {1}{2}\right ) \, \sqrt {2} a^{5} c^{4} \left (-\frac {1}{a^{13} c^{11}}\right )^{\frac {3}{8}} + \sqrt {x}\right ) + 15 \, \sqrt {2} {\left (-\left (i - 1\right ) \, a c^{3} x^{8} - \left (2 i - 2\right ) \, a^{2} c^{2} x^{4} - \left (i - 1\right ) \, a^{3} c\right )} \left (-\frac {1}{a^{13} c^{11}}\right )^{\frac {1}{8}} \log \left (-\left (\frac {1}{2} i + \frac {1}{2}\right ) \, \sqrt {2} a^{5} c^{4} \left (-\frac {1}{a^{13} c^{11}}\right )^{\frac {3}{8}} + \sqrt {x}\right ) + 30 \, {\left (a c^{3} x^{8} + 2 \, a^{2} c^{2} x^{4} + a^{3} c\right )} \left (-\frac {1}{a^{13} c^{11}}\right )^{\frac {1}{8}} \log \left (a^{5} c^{4} \left (-\frac {1}{a^{13} c^{11}}\right )^{\frac {3}{8}} + \sqrt {x}\right ) + 30 \, {\left (-i \, a c^{3} x^{8} - 2 i \, a^{2} c^{2} x^{4} - i \, a^{3} c\right )} \left (-\frac {1}{a^{13} c^{11}}\right )^{\frac {1}{8}} \log \left (i \, a^{5} c^{4} \left (-\frac {1}{a^{13} c^{11}}\right )^{\frac {3}{8}} + \sqrt {x}\right ) + 30 \, {\left (i \, a c^{3} x^{8} + 2 i \, a^{2} c^{2} x^{4} + i \, a^{3} c\right )} \left (-\frac {1}{a^{13} c^{11}}\right )^{\frac {1}{8}} \log \left (-i \, a^{5} c^{4} \left (-\frac {1}{a^{13} c^{11}}\right )^{\frac {3}{8}} + \sqrt {x}\right ) - 30 \, {\left (a c^{3} x^{8} + 2 \, a^{2} c^{2} x^{4} + a^{3} c\right )} \left (-\frac {1}{a^{13} c^{11}}\right )^{\frac {1}{8}} \log \left (-a^{5} c^{4} \left (-\frac {1}{a^{13} c^{11}}\right )^{\frac {3}{8}} + \sqrt {x}\right ) - 16 \, {\left (3 \, c x^{5} - 5 \, a x\right )} \sqrt {x}}{1024 \, {\left (a c^{3} x^{8} + 2 \, a^{2} c^{2} x^{4} + a^{3} c\right )}} \]

[In]

integrate(x^(9/2)/(c*x^4+a)^3,x, algorithm="fricas")

[Out]

-1/1024*(15*sqrt(2)*((I - 1)*a*c^3*x^8 + (2*I - 2)*a^2*c^2*x^4 + (I - 1)*a^3*c)*(-1/(a^13*c^11))^(1/8)*log((1/
2*I + 1/2)*sqrt(2)*a^5*c^4*(-1/(a^13*c^11))^(3/8) + sqrt(x)) + 15*sqrt(2)*(-(I + 1)*a*c^3*x^8 - (2*I + 2)*a^2*
c^2*x^4 - (I + 1)*a^3*c)*(-1/(a^13*c^11))^(1/8)*log(-(1/2*I - 1/2)*sqrt(2)*a^5*c^4*(-1/(a^13*c^11))^(3/8) + sq
rt(x)) + 15*sqrt(2)*((I + 1)*a*c^3*x^8 + (2*I + 2)*a^2*c^2*x^4 + (I + 1)*a^3*c)*(-1/(a^13*c^11))^(1/8)*log((1/
2*I - 1/2)*sqrt(2)*a^5*c^4*(-1/(a^13*c^11))^(3/8) + sqrt(x)) + 15*sqrt(2)*(-(I - 1)*a*c^3*x^8 - (2*I - 2)*a^2*
c^2*x^4 - (I - 1)*a^3*c)*(-1/(a^13*c^11))^(1/8)*log(-(1/2*I + 1/2)*sqrt(2)*a^5*c^4*(-1/(a^13*c^11))^(3/8) + sq
rt(x)) + 30*(a*c^3*x^8 + 2*a^2*c^2*x^4 + a^3*c)*(-1/(a^13*c^11))^(1/8)*log(a^5*c^4*(-1/(a^13*c^11))^(3/8) + sq
rt(x)) + 30*(-I*a*c^3*x^8 - 2*I*a^2*c^2*x^4 - I*a^3*c)*(-1/(a^13*c^11))^(1/8)*log(I*a^5*c^4*(-1/(a^13*c^11))^(
3/8) + sqrt(x)) + 30*(I*a*c^3*x^8 + 2*I*a^2*c^2*x^4 + I*a^3*c)*(-1/(a^13*c^11))^(1/8)*log(-I*a^5*c^4*(-1/(a^13
*c^11))^(3/8) + sqrt(x)) - 30*(a*c^3*x^8 + 2*a^2*c^2*x^4 + a^3*c)*(-1/(a^13*c^11))^(1/8)*log(-a^5*c^4*(-1/(a^1
3*c^11))^(3/8) + sqrt(x)) - 16*(3*c*x^5 - 5*a*x)*sqrt(x))/(a*c^3*x^8 + 2*a^2*c^2*x^4 + a^3*c)

Sympy [F(-1)]

Timed out. \[ \int \frac {x^{9/2}}{\left (a+c x^4\right )^3} \, dx=\text {Timed out} \]

[In]

integrate(x**(9/2)/(c*x**4+a)**3,x)

[Out]

Timed out

Maxima [F]

\[ \int \frac {x^{9/2}}{\left (a+c x^4\right )^3} \, dx=\int { \frac {x^{\frac {9}{2}}}{{\left (c x^{4} + a\right )}^{3}} \,d x } \]

[In]

integrate(x^(9/2)/(c*x^4+a)^3,x, algorithm="maxima")

[Out]

1/64*(3*c*x^(11/2) - 5*a*x^(3/2))/(a*c^3*x^8 + 2*a^2*c^2*x^4 + a^3*c) + 15*integrate(1/128*sqrt(x)/(a*c^2*x^4
+ a^2*c), x)

Giac [B] (verification not implemented)

Leaf count of result is larger than twice the leaf count of optimal. 499 vs. \(2 (227) = 454\).

Time = 0.50 (sec) , antiderivative size = 499, normalized size of antiderivative = 1.50 \[ \int \frac {x^{9/2}}{\left (a+c x^4\right )^3} \, dx=-\frac {15 \, \left (\frac {a}{c}\right )^{\frac {3}{8}} \arctan \left (\frac {\sqrt {-\sqrt {2} + 2} \left (\frac {a}{c}\right )^{\frac {1}{8}} + 2 \, \sqrt {x}}{\sqrt {\sqrt {2} + 2} \left (\frac {a}{c}\right )^{\frac {1}{8}}}\right )}{256 \, a^{2} c \sqrt {2 \, \sqrt {2} + 4}} - \frac {15 \, \left (\frac {a}{c}\right )^{\frac {3}{8}} \arctan \left (-\frac {\sqrt {-\sqrt {2} + 2} \left (\frac {a}{c}\right )^{\frac {1}{8}} - 2 \, \sqrt {x}}{\sqrt {\sqrt {2} + 2} \left (\frac {a}{c}\right )^{\frac {1}{8}}}\right )}{256 \, a^{2} c \sqrt {2 \, \sqrt {2} + 4}} + \frac {15 \, \left (\frac {a}{c}\right )^{\frac {3}{8}} \arctan \left (\frac {\sqrt {\sqrt {2} + 2} \left (\frac {a}{c}\right )^{\frac {1}{8}} + 2 \, \sqrt {x}}{\sqrt {-\sqrt {2} + 2} \left (\frac {a}{c}\right )^{\frac {1}{8}}}\right )}{256 \, a^{2} c \sqrt {-2 \, \sqrt {2} + 4}} + \frac {15 \, \left (\frac {a}{c}\right )^{\frac {3}{8}} \arctan \left (-\frac {\sqrt {\sqrt {2} + 2} \left (\frac {a}{c}\right )^{\frac {1}{8}} - 2 \, \sqrt {x}}{\sqrt {-\sqrt {2} + 2} \left (\frac {a}{c}\right )^{\frac {1}{8}}}\right )}{256 \, a^{2} c \sqrt {-2 \, \sqrt {2} + 4}} + \frac {15 \, \left (\frac {a}{c}\right )^{\frac {3}{8}} \log \left (\sqrt {x} \sqrt {\sqrt {2} + 2} \left (\frac {a}{c}\right )^{\frac {1}{8}} + x + \left (\frac {a}{c}\right )^{\frac {1}{4}}\right )}{512 \, a^{2} c \sqrt {2 \, \sqrt {2} + 4}} - \frac {15 \, \left (\frac {a}{c}\right )^{\frac {3}{8}} \log \left (-\sqrt {x} \sqrt {\sqrt {2} + 2} \left (\frac {a}{c}\right )^{\frac {1}{8}} + x + \left (\frac {a}{c}\right )^{\frac {1}{4}}\right )}{512 \, a^{2} c \sqrt {2 \, \sqrt {2} + 4}} - \frac {15 \, \left (\frac {a}{c}\right )^{\frac {3}{8}} \log \left (\sqrt {x} \sqrt {-\sqrt {2} + 2} \left (\frac {a}{c}\right )^{\frac {1}{8}} + x + \left (\frac {a}{c}\right )^{\frac {1}{4}}\right )}{512 \, a^{2} c \sqrt {-2 \, \sqrt {2} + 4}} + \frac {15 \, \left (\frac {a}{c}\right )^{\frac {3}{8}} \log \left (-\sqrt {x} \sqrt {-\sqrt {2} + 2} \left (\frac {a}{c}\right )^{\frac {1}{8}} + x + \left (\frac {a}{c}\right )^{\frac {1}{4}}\right )}{512 \, a^{2} c \sqrt {-2 \, \sqrt {2} + 4}} + \frac {3 \, c x^{\frac {11}{2}} - 5 \, a x^{\frac {3}{2}}}{64 \, {\left (c x^{4} + a\right )}^{2} a c} \]

[In]

integrate(x^(9/2)/(c*x^4+a)^3,x, algorithm="giac")

[Out]

-15/256*(a/c)^(3/8)*arctan((sqrt(-sqrt(2) + 2)*(a/c)^(1/8) + 2*sqrt(x))/(sqrt(sqrt(2) + 2)*(a/c)^(1/8)))/(a^2*
c*sqrt(2*sqrt(2) + 4)) - 15/256*(a/c)^(3/8)*arctan(-(sqrt(-sqrt(2) + 2)*(a/c)^(1/8) - 2*sqrt(x))/(sqrt(sqrt(2)
+ 2)*(a/c)^(1/8)))/(a^2*c*sqrt(2*sqrt(2) + 4)) + 15/256*(a/c)^(3/8)*arctan((sqrt(sqrt(2) + 2)*(a/c)^(1/8) + 2
*sqrt(x))/(sqrt(-sqrt(2) + 2)*(a/c)^(1/8)))/(a^2*c*sqrt(-2*sqrt(2) + 4)) + 15/256*(a/c)^(3/8)*arctan(-(sqrt(sq
rt(2) + 2)*(a/c)^(1/8) - 2*sqrt(x))/(sqrt(-sqrt(2) + 2)*(a/c)^(1/8)))/(a^2*c*sqrt(-2*sqrt(2) + 4)) + 15/512*(a
/c)^(3/8)*log(sqrt(x)*sqrt(sqrt(2) + 2)*(a/c)^(1/8) + x + (a/c)^(1/4))/(a^2*c*sqrt(2*sqrt(2) + 4)) - 15/512*(a
/c)^(3/8)*log(-sqrt(x)*sqrt(sqrt(2) + 2)*(a/c)^(1/8) + x + (a/c)^(1/4))/(a^2*c*sqrt(2*sqrt(2) + 4)) - 15/512*(
a/c)^(3/8)*log(sqrt(x)*sqrt(-sqrt(2) + 2)*(a/c)^(1/8) + x + (a/c)^(1/4))/(a^2*c*sqrt(-2*sqrt(2) + 4)) + 15/512
*(a/c)^(3/8)*log(-sqrt(x)*sqrt(-sqrt(2) + 2)*(a/c)^(1/8) + x + (a/c)^(1/4))/(a^2*c*sqrt(-2*sqrt(2) + 4)) + 1/6
4*(3*c*x^(11/2) - 5*a*x^(3/2))/((c*x^4 + a)^2*a*c)

Mupad [B] (verification not implemented)

Time = 5.50 (sec) , antiderivative size = 156, normalized size of antiderivative = 0.47 \[ \int \frac {x^{9/2}}{\left (a+c x^4\right )^3} \, dx=\frac {\frac {3\,x^{11/2}}{64\,a}-\frac {5\,x^{3/2}}{64\,c}}{a^2+2\,a\,c\,x^4+c^2\,x^8}-\frac {15\,\mathrm {atan}\left (\frac {c^{1/8}\,\sqrt {x}}{{\left (-a\right )}^{1/8}}\right )}{256\,{\left (-a\right )}^{13/8}\,c^{11/8}}-\frac {\mathrm {atan}\left (\frac {c^{1/8}\,\sqrt {x}\,1{}\mathrm {i}}{{\left (-a\right )}^{1/8}}\right )\,15{}\mathrm {i}}{256\,{\left (-a\right )}^{13/8}\,c^{11/8}}+\frac {\sqrt {2}\,\mathrm {atan}\left (\frac {\sqrt {2}\,c^{1/8}\,\sqrt {x}\,\left (\frac {1}{2}-\frac {1}{2}{}\mathrm {i}\right )}{{\left (-a\right )}^{1/8}}\right )\,\left (\frac {15}{512}-\frac {15}{512}{}\mathrm {i}\right )}{{\left (-a\right )}^{13/8}\,c^{11/8}}+\frac {\sqrt {2}\,\mathrm {atan}\left (\frac {\sqrt {2}\,c^{1/8}\,\sqrt {x}\,\left (\frac {1}{2}+\frac {1}{2}{}\mathrm {i}\right )}{{\left (-a\right )}^{1/8}}\right )\,\left (\frac {15}{512}+\frac {15}{512}{}\mathrm {i}\right )}{{\left (-a\right )}^{13/8}\,c^{11/8}} \]

[In]

int(x^(9/2)/(a + c*x^4)^3,x)

[Out]

((3*x^(11/2))/(64*a) - (5*x^(3/2))/(64*c))/(a^2 + c^2*x^8 + 2*a*c*x^4) - (15*atan((c^(1/8)*x^(1/2))/(-a)^(1/8)
))/(256*(-a)^(13/8)*c^(11/8)) - (atan((c^(1/8)*x^(1/2)*1i)/(-a)^(1/8))*15i)/(256*(-a)^(13/8)*c^(11/8)) + (2^(1
/2)*atan((2^(1/2)*c^(1/8)*x^(1/2)*(1/2 - 1i/2))/(-a)^(1/8))*(15/512 - 15i/512))/((-a)^(13/8)*c^(11/8)) + (2^(1
/2)*atan((2^(1/2)*c^(1/8)*x^(1/2)*(1/2 + 1i/2))/(-a)^(1/8))*(15/512 + 15i/512))/((-a)^(13/8)*c^(11/8))